Home » The World Snooker Championship produced the top sixteen Zhao Xintong and Yan Bingtao hit the top eight and faced the test

The World Snooker Championship produced the top sixteen Zhao Xintong and Yan Bingtao hit the top eight and faced the test

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The World Snooker Championship produced the top sixteen Zhao Xintong and Yan Bingtao hit the top eight and faced the test

  Original title: Snooker World Championships produced top sixteen Zhao Xintong Yan Bingtao hit the top eight and faced the test

With the championship favorite Trump defeated his opponent 10:4, all the top 16 of the 2022 World Snooker Championships will be produced, and 13 seed players will advance smoothly. Among them, two Chinese players Zhao Xintong and Yan Bingtao are shortlisted and will be in the top 8. Challenged in the competition.

The 2022 Snooker World Championships ended the sixth day of the main competition on the 22nd, Beijing time. In the last two games of the first round that day, there were upsets. The No. 11 seed and Belgian brother Brecher lost to Thailand’s Sankham, who broke through the qualifying round. He stopped at 5:10 and became the main match of the World Championships. The third seeded player in the first round. Before him, the two world champions Hawkins and Murphy were upset by the qualifying players Page and Maguire respectively.

In another event on the same day, the 2019 World Championships champion and fourth seed Trump beat Iranian star Wafi, who had entered the World Championships for the first time, 10:4, becoming the last player to advance to the top 16.

A total of 24 players from the Chinese legion competed in the qualifying rounds of the World Championships. Only two players, Ding Junhui and Lv Haotian, made it out of the siege and joined the seeded players Zhao Xintong and Yan Bingtao in the main match. In the first round, Ding Junhui and Lv Haotian were unfortunately eliminated, while Zhao Xintong and Yan Bingtao advanced to the top 16.

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With all the top 16 announced, the second round of the World Championships matchups are also released. First half: Selby vs Yan Bingtao, Page vs Williams, Wilson vs Bingham, McGill vs Trump; second half: Robertson vs Lisowski, Sankham vs Higgins, Zhao Xintong vs Maguire, Allen vs O’Sullivan.

The second round will take 13 wins of 25 rounds, and the game will be divided into 3 stages. It can be seen from the confrontation situation that both Chinese players will face severe tests.

Although Zhao Xintong, who has won two consecutive ranking championships this season, is one of the hottest figures in the snooker field, Maguire, a 41-year-old veteran who once ranked second in the world, has long been famous. Good, ranking down. In the first round of the World Championships, Maguire eliminated Murphy strongly, showing a recovery trend.

The match between Zhao Xintong and Maguire in the first stage of the second round started on the morning of the 22nd, Beijing time. After leading 3:2, Zhao Xintong lost 3 games in a row and temporarily fell behind 3:5. The second and third stages of the 2-person competition will be held on the evening of the 22nd and 23rd, Beijing time, respectively.

Another Chinese player, Yan Bingtao, will face defending champion Selby in the second round. Although he is far inferior to his opponents in terms of ranking, fame and qualifications, as the first “post-00” player to win the ranking championship, Yan Bingtao also has enough confidence. At this year’s German Masters, after Yan Bingtao defeated Selby 5:4, he has “three kills” in the last three confrontations, the four-time world champion.

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This is the third time in a row that Yan Bingtao has entered the second round of the World Championships. He has stopped in the top 16 in the first two times. Whether he can beat the defending champion and advance to the top 8 this time has also become a major suspense in the second round. Aspect. The three-stage match between Yan Bingtao and Selby will be held on the evening of the 22nd, the evening of the 23rd and the early morning of the 24th, Beijing time, respectively.

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