The Snooker World Open semi-finals came to an exciting conclusion last night in Yushan, Jiangxi, with Chinese player Ding Junhui securing a spot in the finals after a thrilling 6-5 victory over Australian player Neil Robertson.
The semi-final match was a best-of-11 game, and Ding Junhui initially struggled, falling behind 1-3 after four games. However, after a halftime break where he took the time to practice and make adjustments, Ding Junhui came back strong, winning three consecutive games to take the lead at 4-3. Despite Robertson’s efforts to rally and take the lead at 5-4, Ding Junhui remained calm and composed, eventually tying the score at 5 and forcing a deciding game.
In the nail-biting final game, Robertson initially took the lead but made a crucial error, allowing Ding Junhui to capitalize and secure the win. Ding Junhui’s victory marks his first appearance in an official ranking championship final in over four years, and he is determined to make the most of this opportunity.
The stage is set for an epic final showdown, as Ding Junhui will face off against Trump, the 2019 World Open champion, in a best-of-19 game system. Trump, who has been in excellent form this season with four championships under his belt, will be a formidable opponent for Ding Junhui.
The final match is set to take place this afternoon and evening, with fans eagerly anticipating the outcome as Ding Junhui aims to claim his first ranking championship title since 2019. Stay tuned for more updates on the Snooker World Open championship match between Ding Junhui and Trump.